मराठी

Π / 2 ∫ − π / 2 Cos 2 X D X . - Mathematics

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प्रश्न

\[\int\limits_{- \pi/2}^{\pi/2} \cos^2 x\ dx .\]
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उत्तर

\[\int_{- \frac{\pi}{2}}^\frac{\pi}{2} \cos^2 x\ d x\]

\[ = \int_{- \frac{\pi}{2}}^\frac{\pi}{2} \frac{1 + \cos2x}{2} dx\]

\[ = \frac{1}{2} \int_{- \frac{\pi}{2}}^\frac{\pi}{2} \left( 1 + \cos2x \right) dx\]

\[ = \frac{1}{2} \left[ x + \frac{\sin2x}{2} \right]_{- \frac{\pi}{2}}^\frac{\pi}{2} \]

\[ = \frac{1}{2}\left( \frac{\pi}{2} + 0 + \frac{\pi}{2} - 0 \right)\]

\[ = \frac{\pi}{2}\]

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Definite Integrals
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पाठ 20: Definite Integrals - Very Short Answers [पृष्ठ ११५]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 20 Definite Integrals
Very Short Answers | Q 4 | पृष्ठ ११५

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