मराठी

Π / 3 ∫ π / 6 1 1 + √ Cot X D X is (A) π/3 (B) π/6 (C) π/12 (D) π/2 - Mathematics

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प्रश्न

\[\int\limits_{\pi/6}^{\pi/3} \frac{1}{1 + \sqrt{\cot}x} dx\] is

पर्याय

  •  π/3

  •  π/6

  • π/12

  • π/2

MCQ
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उत्तर

\[\frac{\pi}{12}\]
\[Let\, I = \int_\frac{\pi}{6}^\frac{\pi}{3} \frac{1}{1 + \sqrt{cotx}} d x .............(1)\]
\[ = \int_\frac{\pi}{6}^\frac{\pi}{3} \frac{1}{1 + \sqrt{cot\left( \frac{\pi}{3} + \frac{\pi}{6} - x \right)}} dx ..............\left[\text{Using }\int_a^b f\left( x \right) d x = \int_a^b f\left( a + b - x \right) d x \right]\]
\[ = \int_\frac{\pi}{6}^\frac{\pi}{3} \frac{1}{1 + \sqrt{\tan x}} d x .................(2)\]
Adding (1) and (2) we get
\[2I = \int_\frac{\pi}{6}^\frac{\pi}{3} \left[ \frac{1}{1 + \sqrt{cotx}} + \frac{1}{1 + \sqrt{\tan x}} \right] d x \]
\[ = \int_\frac{\pi}{6}^\frac{\pi}{3} \frac{2 + \sqrt{cotx} + \sqrt{\tan x}}{\left( 1 + \sqrt{cotx} \right)\left( 1 + \sqrt{\tan x} \right)}dx\]
\[ = \int_\frac{\pi}{6}^\frac{\pi}{3} \left[ \frac{2 + \sqrt{cotx} + \sqrt{\tan x}}{2 + \sqrt{cotx} + \sqrt{\tan x}} \right]dx \]
\[ = \int_\frac{\pi}{6}^\frac{\pi}{3} dx\]
\[ = \left[ x \right]_\frac{\pi}{6}^\frac{\pi}{3} \]
\[ = \frac{\pi}{3} - \frac{\pi}{6}\]
\[ = \frac{\pi}{6}\]
\[\text{Hence, }I = \frac{\pi}{12}\]

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Definite Integrals
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पाठ 20: Definite Integrals - MCQ [पृष्ठ ११८]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 20 Definite Integrals
MCQ | Q 12 | पृष्ठ ११८

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