Advertisements
Advertisements
प्रश्न
\[\int\limits_0^{( \pi )^{2/3}} \sqrt{x} \cos^2 x^{3/2} dx\]
Advertisements
उत्तर
\[Let\ I = \int_0^{( \pi )^\frac{2}{3}} \sqrt{x} \cos^2 x^\frac{3}{2} d x . Then, \]
\[Let\ x^\frac{3}{2} = t . Then, \frac{3}{2}\sqrt{x} dx = dt\]
\[When\ x = 0, t = 0\ and\ x = \left( \pi \right)^\frac{2}{3} , t = \pi\]
\[ \therefore I = \frac{2}{3} \int_0^\pi \cos^2 t dt\]
\[ \Rightarrow I = \frac{2}{3} \int_0^\pi \frac{1 + \cos 2x}{2} dx\]
\[ \Rightarrow I = \frac{1}{3} \left[ x + \frac{\sin 2x}{2} \right]_0^\pi \]
\[ \Rightarrow I = \frac{1}{3}\left( \pi + 0 \right)\]
\[ \Rightarrow I = \frac{\pi}{3}\]
APPEARS IN
संबंधित प्रश्न
Evaluate the following integral:
Evaluate the following integral:
If \[\int\limits_0^1 \left( 3 x^2 + 2x + k \right) dx = 0,\] find the value of k.
The value of the integral \[\int\limits_0^\infty \frac{x}{\left( 1 + x \right)\left( 1 + x^2 \right)} dx\]
The value of \[\int\limits_{- \pi}^\pi \sin^3 x \cos^2 x\ dx\] is
The value of the integral \[\int\limits_{- 2}^2 \left| 1 - x^2 \right| dx\] is ________ .
\[\int\limits_0^{2a} f\left( x \right) dx\] is equal to
Evaluate : \[\int\frac{dx}{\sin^2 x \cos^2 x}\] .
\[\int\limits_1^3 \left| x^2 - 4 \right| dx\]
\[\int\limits_0^{2\pi} \cos^7 x dx\]
\[\int\limits_1^4 \left( x^2 + x \right) dx\]
Evaluate the following:
`Γ (9/2)`
Evaluate `int (x^2 + x)/(x^4 - 9) "d"x`
Verify the following:
`int (x - 1)/(2x + 3) "d"x = x - log |(2x + 3)^2| + "C"`
Evaluate the following:
`int ((x^2 + 2))/(x + 1) "d"x`
`int "e"^x ((1 - x)/(1 + x^2))^2 "d"x` is equal to ______.
