Advertisements
Advertisements
प्रश्न
\[\int\limits_0^4 x dx\]
Advertisements
उत्तर
\[\int_0^4 x d x\]
\[ = \left[ \frac{x^2}{2} \right]_0^4 \]
\[ = 8 - 0\]
\[ = 8\]
APPEARS IN
संबंधित प्रश्न
Evaluate each of the following integral:
The derivative of \[f\left( x \right) = \int\limits_{x^2}^{x^3} \frac{1}{\log_e t} dt, \left( x > 0 \right),\] is
Evaluate : \[\int\limits_0^{2\pi} \cos^5 x dx\] .
\[\int\limits_0^1 \frac{1 - x}{1 + x} dx\]
\[\int\limits_0^{\pi/3} \frac{\cos x}{3 + 4 \sin x} dx\]
\[\int\limits_0^{\pi/2} \frac{\sin x}{\sqrt{1 + \cos x}} dx\]
\[\int\limits_0^{\pi/4} \sin 2x \sin 3x dx\]
\[\int\limits_0^\pi \frac{x \tan x}{\sec x + \tan x} dx\]
\[\int\limits_0^\pi \frac{dx}{6 - \cos x}dx\]
\[\int\limits_1^4 \left( x^2 + x \right) dx\]
\[\int\limits_0^2 \left( x^2 + 2 \right) dx\]
Evaluate the following:
`int_0^oo "e"^(-4x) x^4 "d"x`
Evaluate `int sqrt((1 + x)/(1 - x)) "d"x`, x ≠1
Find `int sqrt(10 - 4x + 4x^2) "d"x`
Find: `int logx/(1 + log x)^2 dx`
