Advertisements
Advertisements
प्रश्न
Choose the correct alternative:
`int_0^oo x^4"e"^-x "d"x` is
पर्याय
12
4
4!
64
MCQ
Advertisements
उत्तर
4!
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
\[\int\limits_0^{1/2} \frac{1}{\sqrt{1 - x^2}} dx\]
\[\int\limits_0^{( \pi )^{2/3}} \sqrt{x} \cos^2 x^{3/2} dx\]
\[\int_{- \frac{\pi}{2}}^\frac{\pi}{2} \left( 2\sin\left| x \right| + \cos\left| x \right| \right)dx\]
\[\int\limits_0^{\pi/2} \frac{\sqrt{\cot x}}{\sqrt{\cot x} + \sqrt{\tan x}} dx\]
\[\int\limits_1^4 \left( x^2 - x \right) dx\]
\[\int\limits_0^\pi \cos^5 x\ dx .\]
\[\int\limits_2^3 \frac{1}{x}dx\]
\[\int\limits_0^{\pi/2} \frac{\sin x}{\sin x + \cos x} dx\] equals to
\[\int\limits_0^4 x\sqrt{4 - x} dx\]
\[\int\limits_0^1 \left| 2x - 1 \right| dx\]
