मराठी

By using the properties of the definite integral, evaluate the integral: ∫0π2 cos5 xdxsin5x+cos5x

Advertisements
Advertisements

प्रश्न

By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2)  (cos^5  xdx)/(sin^5 x + cos^5 x)`

बेरीज
Advertisements

उत्तर

Let `I = int_0^(pi/2) (cos^5 x)/ (sin^5 x + cos ^5 x)  dx`     ....(i)

Also, `I = int_0^(pi/2) (cos^5 (pi/2 - x))/(sin^5 (pi/2 - x) + cos^5 (pi/2 - x)) dx`

`[∵ int_0^a f (x) dx = int_0^a f (a - x) dx]`

`= int_0^(pi/2) (sin^5 x)/ (cos^5x + sin^5 x)  dx`           ....(ii)

Adding (i) and (ii), we have

`2 I = int_0^(pi/2) (cos^5x)/(cos^5x + sin^5 x)  dx + int_0^(pi/2) (sin^5x)/ (cos^5 x + sin^5 x)  dx`

`= int_0^(pi/2) (cos^5 x + sin^5 x)/ (cos^5 x + sin^5 x) dx`

`= int_0^(pi/2) 1 dx = [x]_0^(pi/2) = pi/2`

Hence, `I = pi/4`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Integrals - Exercise 7.11 [पृष्ठ ३४७]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 7 Integrals
Exercise 7.11 | Q 4 | पृष्ठ ३४७

संबंधित प्रश्‍न

If `int_0^alpha3x^2dx=8` then the value of α is :

(a) 0

(b) -2

(c) 2 

(d) ±2


 
 

Evaluate `int_(-2)^2x^2/(1+5^x)dx`

 
 

Evaluate: `int_(-a)^asqrt((a-x)/(a+x)) dx`


By using the properties of the definite integral, evaluate the integral:

`int_2^8 |x - 5| dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^(2x) cos^5 xdx`


Evaluate the definite integrals `int_0^pi (x tan x)/(sec x + tan x)dx`


Evaluate: `int_1^4 {|x -1|+|x - 2|+|x - 4|}dx`


\[\int\limits_0^a 3 x^2 dx = 8,\] find the value of a.


Evaluate : `int  "e"^(3"x")/("e"^(3"x") + 1)` dx


Using properties of definite integrals, evaluate 

`int_0^(π/2)  sqrt(sin x )/ (sqrtsin x + sqrtcos x)dx`


`int_0^2 e^x dx` = ______.


`int_1^2 1/(2x + 3)  dx` = ______


`int_2^4 x/(x^2 + 1)  "d"x` = ______


Evaluate `int_1^2 (sqrt(x))/(sqrt(3 - x) + sqrt(x))  "d"x`


`int_0^(pi/4) (sec^2 x)/((1 + tan x)(2 + tan x))`dx = ?


The value of `int_-3^3 ("a"x^5 + "b"x^3 + "c"x + "k")"dx"`, where a, b, c, k are constants, depends only on ______.


`int_0^{pi/2} xsinx dx` = ______


`int_(pi/18)^((4pi)/9) (2 sqrt(sin x))/(sqrt (sin x) + sqrt(cos x))` dx = ?


`int_-2^1 dx/(x^2 + 4x + 13)` = ______


`int_0^1 "dx"/(sqrt(1 + x) - sqrtx)` = ?


If `int_0^"k" "dx"/(2 + 32x^2) = pi/32,` then the value of k is ______.


The value of `int_2^7 (sqrtx)/(sqrt(9 - x) + sqrtx)dx` is ______ 


`int_0^1 "e"^(5logx) "d"x` = ______.


`int (dx)/(e^x + e^(-x))` is equal to ______.


If `f(a + b - x) = f(x)`, then `int_0^b x f(x)  dx` is equal to


Evaluate: `int_2^5 sqrt(x)/(sqrt(x) + sqrt(7) - x)dx`


If `int_0^1(sqrt(2x) - sqrt(2x - x^2))dx = int_0^1(1 - sqrt(1 - y^2) - y^2/2)dy + int_1^2(2 - y^2/2)dy` + I then I equal.


`int_0^π(xsinx)/(1 + cos^2x)dx` equals ______.


Let `int_0^∞ (t^4dt)/(1 + t^2)^6 = (3π)/(64k)` then k is equal to ______.


`int_0^(π/2)((root(n)(secx))/(root(n)(secx + root(n)("cosec"  x))))dx` is equal to ______.


Evaluate: `int_1^3 sqrt(x + 5)/(sqrt(x + 5) + sqrt(9 - x))dx`


Evaluate `int_0^(π//4) log (1 + tanx)dx`.


If `int_0^(2π) cos^2 x  dx = k int_0^(π/2) cos^2 x  dx`, then the value of k is ______.


Evaluate: `int_0^(π/4) log(1 + tanx)dx`.


Evaluate the following integral:

`int_0^1 x(1-x)^5 dx`


Solve the following.

`int_1^3 x^2 logx  dx`


If `int_0^1(3x^2 + 2x+a)dx = 0,` then a = ______


Evaluate the following integral:

`int_-9^9 x^3/(4 - x^2) dx`


`int_(pi"/"11)^(9pi"/"22) (dx)/(1 + sqrttan x)` =


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×