मराठी

By using the properties of the definite integral, evaluate the integral: ∫0π2(2logsinx-logsin2x)dx

Advertisements
Advertisements

प्रश्न

By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2) (2log sin x - log sin 2x)dx`

बेरीज
Advertisements

उत्तर

Let `I = int_0^(pi/2) (2 log sin x - log sin 2x) dx`

`= int_0^(pi/2) [2 log sin x - log (2 sin x cos x)] dx`

`= int_0^(pi/2) [2 log sinx  - log 2 - log sin x -  log cos x] dx`

`= int_0^(pi/2) [log sin x -  log 2 - log cos x] dx`

`= int_0^(pi/2) log sin x dx - int_0^(pi/2) log 2 dx - int_0^(pi/2) log cos x dx`

`= int_0^(pi/2) log sin x dx - int_0^(pi/2) log 2 dx - int_0^(pi/2) log cos (pi/2 - x)  dx`       `....[∵ int_0^a f (x) dx = int_0^a  f (a - x) dx]`

`= int_0^(pi/2) log sinx dx - (log 2) [x]_0^(pi/2) - int_0^(pi/2) log sin x dx`

`= - (log 2) (pi/2 - 0)`

`= pi/2 log2`

`= pi/2 log (2)^-1`

`= pi/2 log (1/2)`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Integrals - Exercise 7.11 [पृष्ठ ३४७]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 7 Integrals
Exercise 7.11 | Q 10 | पृष्ठ ३४७

संबंधित प्रश्‍न

Evaluate : `intsec^nxtanxdx`


 
 

Evaluate `int_(-2)^2x^2/(1+5^x)dx`

 
 

By using the properties of the definite integral, evaluate the integral:

`int_2^8 |x - 5| dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^1 x(1-x)^n dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^a  sqrtx/(sqrtx + sqrt(a-x))   dx`


Evaluate the definite integrals `int_0^pi (x tan x)/(sec x + tan x)dx`


Evaluate : `int _0^(pi/2) "sin"^ 2  "x"  "dx"`


Find `dy/dx, if y = cos^-1 ( sin 5x)`


`int_0^1 "e"^(2x) "d"x` = ______


`int_0^{pi/2} log(tanx)dx` = ______


`int_0^{pi/2} xsinx dx` = ______


`int_0^(pi/2) sqrt(cos theta) * sin^2 theta "d" theta` = ______.


The value of `int_1^3 dx/(x(1 + x^2))` is ______ 


`int_{pi/6}^{pi/3} sin^2x dx` = ______ 


If `int_0^"k" "dx"/(2 + 32x^2) = pi/32,` then the value of k is ______.


`int_(-1)^1 log ((2 - x)/(2 + x)) "dx" = ?`


`int_0^(pi/2) 1/(1 + cos^3x) "d"x` = ______.


Evaluate `int_0^(pi/2) (tan^7x)/(cot^7x + tan^7x) "d"x`


`int_((-pi)/4)^(pi/4) "dx"/(1 + cos2x)` is equal to ______.


`int_0^(2"a") "f"("x") "dx" = int_0^"a" "f"("x") "dx" + int_0^"a" "f"("k" - "x") "dx"`, then the value of k is:


`int (dx)/(e^x + e^(-x))` is equal to ______.


Let a be a positive real number such that `int_0^ae^(x-[x])dx` = 10e – 9 where [x] is the greatest integer less than or equal to x. Then, a is equal to ______.


The integral `int_0^2||x - 1| -x|dx` is equal to ______.


If f(x) = `(2 - xcosx)/(2 + xcosx)` and g(x) = logex, (x > 0) then the value of the integral `int_((-π)/4)^(π/4) "g"("f"(x))"d"x` is ______.


Let `int_0^∞ (t^4dt)/(1 + t^2)^6 = (3π)/(64k)` then k is equal to ______.


If f(x) = `{{:(x^2",", "where"  0 ≤ x < 1),(sqrt(x)",", "when"  1 ≤ x < 2):}`, then `int_0^2f(x)dx` equals ______.


`int_(π/3)^(π/2) x sin(π[x] - x)dx` is equal to ______.


`int_0^(π/4) x. sec^2 x  dx` = ______.


 `int_-9^9 x^3/(4-x^2) dx` =______


Evaluate the following definite integral:

`int_1^3 log x  dx`


Evaluate the following integral:

`int_-9^9 x^3/(4 - x^2) dx`


Solve the following.

`int_0^1e^(x^2)x^3 dx`


Solve the following.

`int_0^1 e^(x^2) x^3dx`


Evaluate the following integral:

`int_-9^9x^3/(4-x^2)dx`


Evaluate the following integrals:

`int_-9^9 x^3/(4 - x^3 ) dx`


Evaluate the following integral:

`int_0^1x(1-x)^5dx`


`∫_0^(π/2) (sqrttan x + sqrtcot x)dx` = ______.


What is the value of a definite integral when its upper and lower limits are equal?


When is \[P_4\] : Special Case of \[P_3\] applied?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×