English
Karnataka Board PUCPUC Science Class 11

The Time Period of a Particle in Simple Harmonic Motion is Equal to the Time Between Consecutive Appearances of the Particle at a Particular Point in Its Motion. - Physics

Advertisements
Advertisements

Question

The time period of a particle in simple harmonic motion is equal to the time between consecutive appearances of the particle at a particular point in its motion. This point is

Options

  • the mean position

  • an extreme position

  • between the mean position and the positive extreme

  • between the mean position and the negative extreme

MCQ
Advertisements

Solution

an extreme position

One oscillation is said to be completed when the particle returns to the extreme position i.e. from where it started.

shaalaa.com
  Is there an error in this question or solution?
Chapter 12: Simple Harmonics Motion - MCQ [Page 250]

APPEARS IN

HC Verma Concepts of Physics Vol. 1 [English] Class 11 and 12
Chapter 12 Simple Harmonics Motion
MCQ | Q 2 | Page 250

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Assuming the expression for displacement of a particle starting from extreme position, explain graphically the variation of velocity and acceleration w.r.t. time.


A body of mass 1 kg is made to oscillate on a spring of force constant 16 N/m. Calculate:

a) Angular frequency

b) frequency of vibration.


A particle executing simple harmonic motion comes to rest at the extreme positions. Is the resultant force on the particle zero at these positions according to Newton's first law?


In measuring time period of a pendulum, it is advised to measure the time between consecutive passage through the mean position in the same direction. This is said to result in better accuracy than measuring time between consecutive passage through an extreme position. Explain.


A hollow sphere filled with water is used as the bob of a pendulum. Assume that the equation for simple pendulum is valid with the distance between the point of suspension and centre of mass of the bob acting as the effective length of the pendulum. If water slowly leaks out of the bob, how will the time period vary?


The displacement of a particle in simple harmonic motion in one time period is


The distance moved by a particle in simple harmonic motion in one time period is


A pendulum clock that keeps correct time on the earth is taken to the moon. It will run


For a particle executing simple harmonic motion, the acceleration is proportional to


In a simple harmonic motion
(a) the maximum potential energy equals the maximum kinetic energy
(b) the minimum potential energy equals the minimum kinetic energy
(c) the minimum potential energy equals the maximum kinetic energy
(d) the maximum potential energy equals the minimum kinetic energy


An object is released from rest. The time it takes to fall through a distance h and the speed of the object as it falls through this distance are measured with a pendulum clock. The entire apparatus is taken on the moon and the experiment is repeated
(a) the measured times are same
(b) the measured speeds are same
(c) the actual times in the fall are equal
(d) the actual speeds are equal


All the surfaces shown in figure are frictionless. The mass of the care is M, that of the block is m and the spring has spring constant k. Initially the car and the block are at rest and the spring is stretched through a length x0 when the system is released. (a) Find the amplitudes of the simple harmonic motion of the block and of the care as seen from the road. (b) Find the time period(s) of the two simple harmonic motions.


Assume that a tunnel is dug across the earth (radius = R) passing through its centre. Find the time a particle takes to cover the length of the tunnel if (a) it is projected into the tunnel with a speed of \[\sqrt{gR}\] (b) it is released from a height R above the tunnel (c) it is thrown vertically upward along the length of tunnel with a speed of \[\sqrt{gR}\]


A simple pendulum of length 1 feet suspended from the ceiling of an elevator takes π/3 seconds to complete one oscillation. Find the acceleration of the elevator.


A simple pendulum fixed in a car has a time period of 4 seconds when the car is moving uniformly on a horizontal road. When the accelerator is pressed, the time period changes to 3.99 seconds. Making an approximate analysis, find the acceleration of the car.


Define the time period of simple harmonic motion.


Displacement vs. time curve for a particle executing S.H.M. is shown in figure. Choose the correct statements.

  1. Phase of the oscillator is same at t = 0 s and t = 2s.
  2. Phase of the oscillator is same at t = 2 s and t = 6s.
  3. Phase of the oscillator is same at t = 1 s and t = 7s.
  4. Phase of the oscillator is same at t = 1 s and t = 5s.

What is the ratio of maxmimum acceleration to the maximum velocity of a simple harmonic oscillator?


Assume there are two identical simple pendulum clocks. Clock - 1 is placed on the earth and Clock - 2 is placed on a space station located at a height h above the earth's surface. Clock - 1 and Clock - 2 operate at time periods 4 s and 6 s respectively. Then the value of h is ______.

(consider the radius of earth RE = 6400 km and g on earth 10 m/s2)


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×