English
Tamil Nadu Board of Secondary EducationHSC Science Class 11

A particle executing SHM crosses points A and B with the same velocity. Having taken 3 s in passing from A to B, it returns to B after another 3 s. The time period is ____________. - Physics

Advertisements
Advertisements

Question

A particle executing SHM crosses points A and B with the same velocity. Having taken 3 s in passing from A to B, it returns to B after another 3 s. The time period is ____________.

Options

  • 15 s

  • 6 s

  • 12 s

  • 9 s

MCQ
Fill in the Blanks
Advertisements

Solution

A particle executing SHM crosses points A and B with the same velocity. Having taken 3 s in passing from A to B, it returns to B after another 3 s. The time period is 12 s.

shaalaa.com
  Is there an error in this question or solution?
Chapter 10: Oscillations - Evaluation [Page 218]

APPEARS IN

Samacheer Kalvi Physics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 10 Oscillations
Evaluation | Q I. 2. | Page 218

RELATED QUESTIONS

Can simple harmonic motion take place in a non-inertial frame? If yes, should the ratio of the force applied with the displacement be constant?


A hollow sphere filled with water is used as the bob of a pendulum. Assume that the equation for simple pendulum is valid with the distance between the point of suspension and centre of mass of the bob acting as the effective length of the pendulum. If water slowly leaks out of the bob, how will the time period vary?


A block of known mass is suspended from a fixed support through a light spring. Can you find the time period of vertical oscillation only by measuring the extension of the spring when the block is in equilibrium?


The displacement of a particle in simple harmonic motion in one time period is


A pendulum clock that keeps correct time on the earth is taken to the moon. It will run


A particle executes simple harmonic motion with an amplitude of 10 cm and time period 6 s. At t = 0 it is at position x = 5 cm going towards positive x-direction. Write the equation for the displacement x at time t. Find the magnitude of the acceleration of the particle at t = 4 s.


A simple pendulum of length 40 cm is taken inside a deep mine. Assume for the time being that the mine is 1600 km deep. Calculate the time period of the pendulum there. Radius of the earth = 6400 km.


In a simple harmonic oscillation, the acceleration against displacement for one complete oscillation will be __________.


What is the ratio of maxmimum acceleration to the maximum velocity of a simple harmonic oscillator?


A container consist of hemispherical shell of radius 'r ' and cylindrical shell of height 'h' radius of same material and thickness. The maximum value h/r so that container remain stable equilibrium in the position shown (neglect friction) is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×