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The Surface Tension of Water at 0ºC is 75·5 dyne/em. Find Surface Tension of Water at 25°C.

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Question

The surface tension of water at 0ºc is 75·5 dyne/cm. Find surface tension of water at 25°C. [ α for water = 0·0021/°C ]

Numerical
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Solution

Given, T0 = 75.5 dyne/cm, α = 0.0027, θ = 25°C
Thus, T = T0 ( 1 - αθ )
            = 75.5 [ 1 - (0.0027)(25) ]
            = 75.5 [ 1 - 0.0675 ]
            = 75.5( 0.9325 )
            = 70.40 dyne/cm
Thus, the surface tension of water at 25°C is 70.40 dyne/cm.
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2012-2013 (March)

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