Advertisements
Advertisements
Question
The speed of a car increases from 10 km/h to 64 km/h in 10 seconds. What will be its acceleration?
Advertisements
Solution
Initial velocity u = 10 km/hr. = (10 X 1000)/3600 = 8.33 ms-1.
Final velocity = 64 km/hr = (64 X 1000)/3600 = 17.77 ms-1.
Time = 10 s.
Acceleration = (v-u)/t = (17.77- 8.33)/10 = 9.44/10 = 0.94 ms-2.
APPEARS IN
RELATED QUESTIONS
Define acceleration. State its unit.
Draw a graph for acceleration against time for a uniformly accelerated motion. How can it be used to find the change in speed in a certain interval of time?
When is the acceleration due to gravity negative?
Give an example of an accelerated body, moving with a uniform speed.
A truck running at 90 kmh−1, is brought to rest over a distance of 25 m. Calculate the retardation and time for which brakes are applied.
The acceleration of a moving body is constant in magnitude and direction. Must the path of the body be a straight line?
If not, given an example.
State if the following situation is possible:
A body moving with constant acceleration but with Zero velocity.
From the given v-t graph it can be inferred that an object is

m/s2 is the unit of ______.
Acceleration is a scalar.
