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The primary of a transformer has 40 turns and works on 100 V and 100 W. Find a number of turns in the secondary to step up the voltage to 400 V. Also calculate the current - Physics

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Question

The primary of a transformer has 40 turns and works on 100 V and 100 W. Find a number of turns in the secondary to step up the voltage to 400 V. Also calculate the current in the secondary and primary.

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Solution

Given:

NP = 40, eP = 100 V, PP = 100 watt, eS = 400 V 

To find:

  1. Number of turns in the secondary (NS)
  2. Current in the secondary (IS)
  3. Current in the primary (IP

Formulae:

  1. `"e"_"p"/"e"_"s" = "N"_"p"/"N"_"s"`
  2. P = Ie

Calculation: 

From formula (i),

`"N"_"s" = "N"_"p" xx "e"_"s"/"e"_"p" = (40 xx 400)/100` 

∴ NS = 160 

For an ideal transformer, PS = P

From formula (ii),

PS = ISeS  

∴ IPeP = ISeS

∴ Is = `("I"_"p""e"_"p")/"e"_"s"` 

= `"P"_"p"/"e"_"s" = 100/400 = 0.25` A

Ip = `"P"_"p"/"e"_"p"`

Ip = `100/100 = 1` A

∴ Ip = 1 A

  1. The number of turns in the secondary is 160.
  2. The current in the secondary is 0.25 A.
  3. The current in the primary is 1 A. 
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Chapter 12: Electromagnetic Induction - Short Answer II

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