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Question
The primary coil of a transformer has 60 turns whereas its secondary coil has 3000 turns.
If a current of 5A flows in the primary coil, how much current will flow in a load in the secondary coil? State the assumption you have made regarding the transformer, in this calculation.
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Solution
Give that, IP = 5 A, IS = ?
`therefore "N"_"S"/"N"_"P" = "I"_"P"/"I"_"S"`
`=> 3000/60 = 5/"I"_"S"`
`"I"_"S" = 1/10`
`"I"_"S"` = 0.1 A
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