Advertisements
Advertisements
Question
The length and breadth of a rectangular piece of land are in the ratio 5 : 3. If the total cost of fencing it at the rate of ₹24 per meter is ₹9600, find its :
(i) length and breadth
(ii) area
(iii) cost of levelling at the rate of ₹60 per m2.
Advertisements
Solution
Ratio in length and breadth of a rectangular piece of land = 5 : 3
Cost of fencing = ₹9600
And rate = ₹24 per m
Perimeter =`"Total cost of fencing"/"Rate per m"`
= `9600/24`
= 400 m
Let length = 5x
Then breadth = 3x
∴ Perimeter = 2(l + b)
400 = 2 × (5x + 3x)
∴ 16x = 400
x = `400/16=25`
(i) ∴ Length of land = 5x = 5 × 25 = 125 m
and breadth = 3x = 3 × 25 = 75 m
(ii) Area = l × b
= 125 × 75 = 9375 m2
(iii) Cost of levelling at rate ₹60 per m2
= ₹60 × 9375 m2 = ₹5,62,500
APPEARS IN
RELATED QUESTIONS
In the below Fig, ABC and ABD are two triangles on the base AB. If line segment CD is
bisected by AB at O, show that ar (Δ ABC) = ar (Δ ABD)

ABCD is a parallelogram whose diagonals intersect at O. If P is any point on BO, prove
that: (1) ar (ΔADO) = ar (ΔCDO) (2) ar (ΔABP) = ar (ΔCBP)
The median of a triangle divides it into two ______.
In the given figure, ABCD is a parallelogram. If AB = 12 cm, AE = 7.5 cm, CF = 15 cm, then AD =

Length of a rectangle is 30 m and its breadth is 20 m. Find the increase in its area if its length is increased by 10 m and its breadth is doubled.
Parth and Gini bought aam papad (dried mango slice) from a shop. Their pieces looked like these. Both could not make out whose piece was bigger.


- Suggest some ways to find out whose piece is bigger. Discuss
A magazine charges Rs 300 per 10 sq cm area for advertising. A company decided to order a half page advertisment. If each page of the magazine is 15 cm × 24 cm, what amount will the company has to pay for it?
Find the area of the following figure by counting squares:

Find the area of the following figure by counting squares:

When using a square centimeter sheet for measurement, the area of one entire square equals:
