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Question
A floor is 40 m long and 15 m broad. It is covered with tiles, each measuring 60 cm by 50 cm. Find the number of tiles required to cover the floor.
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Solution
Length of floor (l) = 40 m
breadth of floor (b) = 15 m
∴ Area of floor = l × b = 40 × 15 = 600 m2
Length of one tile = 60 cm =`6/10` m
and breadth = 50 cm = `5/10` m
∴ Area of one tile = `6/10xx5/10`
= `30/100=3/10"m"^2`
∴ Number of tiles =`"Total area of floor"/"Area of one tile"`
= `600/(3/10)=(600xx10)/3=2000`
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