Question

A floor is 40 m long and 15 m broad. It is covered with tiles, each measuring 60 cm by 50 cm. Find the number of tiles required to cover the floor.

Answer 1

Length of floor (l) = 40 m

breadth of floor (b) = 15 m

∴ Area of floor = l × b = 40 × 15 = 600 m²

Length of one tile = 60 cm =`6/10` m

and breadth = 50 cm = `5/10` m

∴ Area of one tile = `6/10xx5/10`

= `30/100=3/10"m"^2`

∴ Number of tiles =`"Total area of floor"/"Area of one tile"`

= `600/(3/10)=(600xx10)/3=2000`