Advertisements
Advertisements
Question
The side of a square field is 16 m. What will be increase in its area, if each of its sides is doubled?
Advertisements
Solution
Side of a square field (a) = 16 m
∴ Area of a square field = (a)2
= 16 × 16 m2 = 256 m2
Each of its side is doubled
∴ New side = (16 × 2)m = 32 m
∴ New area of the square field = (a)2
= 32 × 32 m2 = 1024 m2
APPEARS IN
RELATED QUESTIONS
Compute the area of trapezium PQRS is Fig. below.

In the below fig. OCDE is a rectangle inscribed in a quadrant of a circle of radius 10 cm. If
OE = 2√5, find the area of the rectangle.

In the below fig. X and Y are the mid-points of AC and AB respectively, QP || BC and
CYQ and BXP are straight lines. Prove that ar (Δ ABP) = ar (ΔACQ).

In the given figure, ABCD is a rectangle in which CD = 6 cm, AD = 8 cm. Find the area of parallelogram CDEF.

In a ΔABC, D, E, F are the mid-points of sides BC, CA and AB respectively. If ar (ΔABC) = 16cm2, then ar (trapezium FBCE) =
In the given figure, ABCD is a parallelogram. If AB = 12 cm, AE = 7.5 cm, CF = 15 cm, then AD =

In the given figure, ABCD and FECG are parallelograms equal in area. If ar (ΔAQE) = 12 cm2, then ar (||gm FGBQ) =

Is the area of the blue shape more than the area of the yellow shape? Why?


Altogether how many squares can be arranged on it?
The King was very happy with carpenters Cheggu and Anar. They had made a very big and beautiful bed for him. So as gifts the king wanted to give some land to Cheggu, and some gold to Anar. Cheggu was happy. He took 100 meters of wire and tried to make different rectangles.
He made a 10 m × 40 m rectangle. Its area was 400 square meters. So he next made a 30 m × 20 m rectangle.
- What other rectangles can he make with 100 meters of wire? Discuss which of these rectangles will have the biggest area.
