Advertisements
Advertisements
प्रश्न
A floor is 40 m long and 15 m broad. It is covered with tiles, each measuring 60 cm by 50 cm. Find the number of tiles required to cover the floor.
Advertisements
उत्तर
Length of floor (l) = 40 m
breadth of floor (b) = 15 m
∴ Area of floor = l × b = 40 × 15 = 600 m2
Length of one tile = 60 cm =`6/10` m
and breadth = 50 cm = `5/10` m
∴ Area of one tile = `6/10xx5/10`
= `30/100=3/10"m"^2`
∴ Number of tiles =`"Total area of floor"/"Area of one tile"`
= `600/(3/10)=(600xx10)/3=2000`
APPEARS IN
संबंधित प्रश्न
In Q. No 1, if AD = 6 cm, CF = 10 cm, and AE = 8cm, find AB.
ABCD is a parallelogram whose diagonals intersect at O. If P is any point on BO, prove
that: (1) ar (ΔADO) = ar (ΔCDO) (2) ar (ΔABP) = ar (ΔCBP)
ABCD is a parallelogram. P is any point on CD. If ar (ΔDPA) = 15 cm2 and ar (ΔAPC) = 20 cm2, then ar (ΔAPB) =
ABCD is a rectangle with O as any point in its interior. If ar (ΔAOD) = 3 cm2 and ar (ΔABOC) = 6 cm2, then area of rectangle ABCD is
Find the area of a rectangle whose length = 8.5 m breadth = 5 m.
Find the area of a square, whose side is: 4.1 cm.
What is the area of the rectangle? ________ square cm
How will you decide? Discuss.
Find the area of the following figure by counting squares:
Which statement correctly describes how area is determined?
