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Question
The integrating factor of the differential equation `"dy"/"dx" (x log x) + y` = 2logx is ______.
Options
ex
log x
log (log x)
x
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Solution
The integrating factor of the differential equation `"dy"/"dx" (x log x) + y` = 2logx is log x.
Explanation:
Given equation can be written as `"dy"/"dx" + y/(xlogx) = 2/x`.
Therefore, I.F. = `"e"^(int 1/(xlogx) "d"x)`
= `"e"^(log (logx))`
= log x.
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