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Question
Show that the function y = A cos x + B sin x is a solution of the differential equation \[\frac{d^2 y}{d x^2} + y = 0\]
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Solution
We have,
\[y = A \cos x + B \sin x............(1)\]
Differentiating both sides of equation (1) with respect to x, we get
\[\frac{dy}{dx} = - A \sin x + B \cos x...........(2)\]
Differentiating both sides of equation (2) with respect to x, we get
\[\frac{d^2 y}{d x^2} = - A \cos x - B \sin x\]
\[ \Rightarrow \frac{d^2 y}{d x^2} = - \left( A \cos x + B \sin x \right)\]
\[ \Rightarrow \frac{d^2 y}{d x^2} = - y ...........\left[\text{Using equation }\left( 1 \right) \right]\]
⇒ \[\frac{d^2 y}{d x^2} + y = 0\]
Hence, the given function is the solution to the given differential equation.
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