English

Choose the correct alternative. The differential equation of y = k1+k2x is

Advertisements
Advertisements

Question

Choose the correct alternative.

The differential equation of y = `k_1 + k_2/x` is

Options

  • `(d^2y)/dx^2 + 2 dy/dx = 0`

  • `x(d^2y)/dx^2 + 2 dy/dx = 0`

  • `(d^2y)/dx^2 -2 dy/dx = 0`

  • `x(d^2y)/dx^2 -2 dy/dx = 0`

MCQ
Advertisements

Solution

The differential equation of `y = k_1 + k_2/x` is `x(d^2y)/dx^2 + 2 dy/dx = 0`

Explanation

`y = k_1 + k_2/x`

∴ xy = xk1 + k2

Differentiating w.r.t. x, we get

`y+x dy/dx = k_1`

Again, differentiating w.r.t. x, we get

`dy/dx + dy/dx + x (d^2y)/dx^2 = 0`

∴ `x (d^2y)/dx^2 + 2 dy/dx = 0`

shaalaa.com
  Is there an error in this question or solution?
Chapter 8: Differential Equation and Applications - Miscellaneous Exercise 8 [Page 171]

APPEARS IN

Balbharati Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
Chapter 8 Differential Equation and Applications
Miscellaneous Exercise 8 | Q 1.03 | Page 171

RELATED QUESTIONS

\[\left( \frac{dy}{dx} \right)^2 + \frac{1}{dy/dx} = 2\]

Assume that a rain drop evaporates at a rate proportional to its surface area. Form a differential equation involving the rate of change of the radius of the rain drop.

 

Show that y = ex (A cos x + B sin x) is the solution of the differential equation \[\frac{d^2 y}{d x^2} - 2\frac{dy}{dx} + 2y = 0\]


\[\frac{dy}{dx} = x^2 + x - \frac{1}{x}, x \neq 0\]

\[\cos x\frac{dy}{dx} - \cos 2x = \cos 3x\]

\[\frac{dy}{dx} = x \log x\]

\[x\left( x^2 - 1 \right)\frac{dy}{dx} = 1, y\left( 2 \right) = 0\]

\[\frac{dy}{dx} = 2xy, y\left( 0 \right) = 1\]

\[2\left( y + 3 \right) - xy\frac{dy}{dx} = 0\], y(1) = −2

\[\cos^2 \left( x - 2y \right) = 1 - 2\frac{dy}{dx}\]

\[x^2 \frac{dy}{dx} = x^2 - 2 y^2 + xy\]

Find the particular solution of the differential equation \[\frac{dy}{dx} = \frac{xy}{x^2 + y^2}\] given that y = 1 when x = 0.

 


Solve the following initial value problem:-
\[x\frac{dy}{dx} - y = \log x, y\left( 1 \right) = 0\]


Solve the following initial value problem:
\[\frac{dy}{dx} + y \cot x = 4x\text{ cosec }x, y\left( \frac{\pi}{2} \right) = 0\]


Solve the following initial value problem:-

\[dy = \cos x\left( 2 - y\text{ cosec }x \right)dx\]


At every point on a curve the slope is the sum of the abscissa and the product of the ordinate and the abscissa, and the curve passes through (0, 1). Find the equation of the curve.


The equation of the curve whose slope is given by \[\frac{dy}{dx} = \frac{2y}{x}; x > 0, y > 0\] and which passes through the point (1, 1) is


The integrating factor of the differential equation \[\left( 1 - y^2 \right)\frac{dx}{dy} + yx = ay\left( - 1 < y < 1 \right)\] is ______.


Solve the following differential equation : \[\left( \sqrt{1 + x^2 + y^2 + x^2 y^2} \right) dx + xy \ dy = 0\].


Form the differential equation of the family of parabolas having vertex at origin and axis along positive y-axis.


The price of six different commodities for years 2009 and year 2011 are as follows: 

Commodities A B C D E F

Price in 2009 (₹)

35 80 25 30 80 x
Price in 2011 (₹) 50 y 45 70 120 105

The Index number for the year 2011 taking 2009 as the base year for the above data was calculated to be 125. Find the values of x andy if the total price in 2009 is ₹ 360.


Solve the following differential equation.

`(dθ)/dt  = − k (θ − θ_0)`


The differential equation of `y = k_1e^x+ k_2 e^-x` is ______.


The integrating factor of the differential equation `dy/dx - y = x` is e−x.


Solve the following differential equation y2dx + (xy + x2) dy = 0


Choose the correct alternative:

Differential equation of the function c + 4yx = 0 is


State whether the following statement is True or False:

The integrating factor of the differential equation `("d"y)/("d"x) - y` = x is e–x 


Verify y = log x + c is the solution of differential equation `x ("d"^2y)/("d"x^2) + ("d"y)/("d"x)` = 0


Integrating factor of the differential equation `x "dy"/"dx" - y` = sinx is ______.


Solve the differential equation

`x + y dy/dx` = x2 + y2


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×