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Determine the order and degree of the following differential equations. Solution D.E y = aex + be−x d2ydx2=1

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Question

Determine the order and degree of the following differential equations.

Solution D.E
y = aex + be−x `(d^2y)/dx^2= 1`
Sum
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Solution

y = aex + be−x  ......(1)

Differentiating w.r.t. x, we get

`dy/dx = ae^x - be^-x`

Again, differentiating w.r.t. x, we get

`(d^2y)/dx^2 = ae^x - be^-x`

∴ `(d^2y)/dx^2 = y` .....[From (i)]

∴ Given function is a solution of the given differential equation.

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Chapter 8: Differential Equation and Applications - Exercise 8.1 [Page 162]

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Balbharati Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
Chapter 8 Differential Equation and Applications
Exercise 8.1 | Q 2.5 | Page 162

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