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प्रश्न
Determine the order and degree of the following differential equations.
| Solution | D.E |
| y = aex + be−x | `(d^2y)/dx^2= 1` |
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उत्तर
y = aex + be−x ......(1)
Differentiating w.r.t. x, we get
`dy/dx = ae^x - be^-x`
Again, differentiating w.r.t. x, we get
`(d^2y)/dx^2 = ae^x - be^-x`
∴ `(d^2y)/dx^2 = y` .....[From (i)]
∴ Given function is a solution of the given differential equation.
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