मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

The solution of differential equation x2d2ydx2 = 1 is ______

Advertisements
Advertisements

प्रश्न

The solution of differential equation `x^2 ("d"^2y)/("d"x^2)` = 1 is ______

रिकाम्या जागा भरा
Advertisements

उत्तर

y = 1 – log x

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1.8: Differential Equation and Applications - Q.2

संबंधित प्रश्‍न

Show that the differential equation of which y = 2(x2 − 1) + \[c e^{- x^2}\] is a solution, is \[\frac{dy}{dx} + 2xy = 4 x^3\]


Verify that y = 4 sin 3x is a solution of the differential equation \[\frac{d^2 y}{d x^2} + 9y = 0\]


Hence, the given function is the solution to the given differential equation. \[\frac{c - x}{1 + cx}\] is a solution of the differential equation \[(1+x^2)\frac{dy}{dx}+(1+y^2)=0\].


Differential equation \[\frac{d^2 y}{d x^2} - y = 0, y \left( 0 \right) = 2, y' \left( 0 \right) = 0\] Function y = ex + ex


\[\frac{dy}{dx} = \frac{1 - \cos x}{1 + \cos x}\]

\[\sqrt{a + x} dy + x\ dx = 0\]

Solve the following differential equation:
\[\text{ cosec }x \log y \frac{dy}{dx} + x^2 y^2 = 0\]


Solve the following differential equation:
\[\left( 1 + y^2 \right) \tan^{- 1} xdx + 2y\left( 1 + x^2 \right)dy = 0\]


\[2x\frac{dy}{dx} = 3y, y\left( 1 \right) = 2\]

\[\frac{dr}{dt} = - rt, r\left( 0 \right) = r_0\]

Find the solution of the differential equation cos y dy + cos x sin y dx = 0 given that y = \[\frac{\pi}{2}\], when x = \[\frac{\pi}{2}\] 

 


\[\left( x + y \right)^2 \frac{dy}{dx} = 1\]

\[\frac{dy}{dx} = \frac{y}{x} - \sqrt{\frac{y^2}{x^2} - 1}\]

Solve the following initial value problem:-

\[\frac{dy}{dx} - 3y \cot x = \sin 2x; y = 2\text{ when }x = \frac{\pi}{2}\]


The surface area of a balloon being inflated, changes at a rate proportional to time t. If initially its radius is 1 unit and after 3 seconds it is 2 units, find the radius after time t.


The rate of increase of bacteria in a culture is proportional to the number of bacteria present and it is found that the number doubles in 6 hours. Prove that the bacteria becomes 8 times at the end of 18 hours.


Which of the following is the integrating factor of (x log x) \[\frac{dy}{dx} + y\] = 2 log x?


The integrating factor of the differential equation \[x\frac{dy}{dx} - y = 2 x^2\]


Form the differential equation representing the family of parabolas having vertex at origin and axis along positive direction of x-axis.


Form the differential equation of the family of circles having centre on y-axis and radius 3 unit.


Determine the order and degree of the following differential equations.

Solution D.E.
ax2 + by2 = 5 `xy(d^2y)/dx^2+ x(dy/dx)^2 = y dy/dx`

Solve the following differential equation.

`(dθ)/dt  = − k (θ − θ_0)`


Solve the following differential equation.

y dx + (x - y2 ) dy = 0


Solve the following differential equation.

`(x + a) dy/dx = – y + a`


Solve: `("d"y)/("d"x) + 2/xy` = x2 


For the differential equation, find the particular solution (x – y2x) dx – (y + x2y) dy = 0 when x = 2, y = 0


Choose the correct alternative:

Solution of the equation `x("d"y)/("d"x)` = y log y is


Solve the following differential equation `("d"y)/("d"x)` = cos(x + y)

Solution: `("d"y)/("d"x)` = cos(x + y)    ......(1)

Put `square`

∴ `1 + ("d"y)/("d"x) = "dv"/("d"x)`

∴ `("d"y)/("d"x) = "dv"/("d"x) - 1`

∴ (1) becomes `"dv"/("d"x) - 1` = cos v

∴ `"dv"/("d"x)` = 1 + cos v

∴ `square` dv = dx

Integrating, we get

`int 1/(1 + cos "v")  "d"v = int  "d"x`

∴ `int 1/(2cos^2 ("v"/2))  "dv" = int  "d"x`

∴ `1/2 int square  "dv" = int  "d"x`

∴ `1/2* (tan("v"/2))/(1/2)` = x + c

∴ `square` = x + c


The differential equation of all non horizontal lines in a plane is `("d"^2x)/("d"y^2)` = 0


What distinguishes an ordinary differential equation from other types of differential equations?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×