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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

The function y = ex is solution ______ of differential equation - Mathematics and Statistics

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प्रश्न

The function y = ex is solution  ______ of differential equation

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उत्तर

`("d"y)/("d"x) = y`

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पाठ 1.8: Differential Equation and Applications - Q.2

संबंधित प्रश्‍न

\[\frac{d^3 x}{d t^3} + \frac{d^2 x}{d t^2} + \left( \frac{dx}{dt} \right)^2 = e^t\]

Show that the function y = A cos x + B sin x is a solution of the differential equation \[\frac{d^2 y}{d x^2} + y = 0\]


\[\frac{dy}{dx} = x^2 + x - \frac{1}{x}, x \neq 0\]

\[\frac{dy}{dx} = \frac{1 - \cos x}{1 + \cos x}\]

\[\sin^4 x\frac{dy}{dx} = \cos x\]

\[y\sqrt{1 + x^2} + x\sqrt{1 + y^2}\frac{dy}{dx} = 0\]

\[\frac{dy}{dx} = \frac{x\left( 2 \log x + 1 \right)}{\sin y + y \cos y}\]

(y2 + 1) dx − (x2 + 1) dy = 0


\[\frac{dy}{dx} = y \tan x, y\left( 0 \right) = 1\]

The volume of a spherical balloon being inflated changes at a constant rate. If initially its radius is 3 units and after 3 seconds it is 6 units. Find the radius of the balloon after `t` seconds.


\[2xy\frac{dy}{dx} = x^2 + y^2\]

\[x^2 \frac{dy}{dx} = x^2 - 2 y^2 + xy\]

3x2 dy = (3xy + y2) dx


Solve the following initial value problem:-

\[y' + y = e^x , y\left( 0 \right) = \frac{1}{2}\]


Show that all curves for which the slope at any point (x, y) on it is \[\frac{x^2 + y^2}{2xy}\]  are rectangular hyperbola.


The slope of a curve at each of its points is equal to the square of the abscissa of the point. Find the particular curve through the point (−1, 1).


Find the equation of the curve that passes through the point (0, a) and is such that at any point (x, y) on it, the product of its slope and the ordinate is equal to the abscissa.


The integrating factor of the differential equation (x log x)
\[\frac{dy}{dx} + y = 2 \log x\], is given by


Solve the following differential equation : \[y^2 dx + \left( x^2 - xy + y^2 \right)dy = 0\] .


Solve the following differential equation.

`(dθ)/dt  = − k (θ − θ_0)`


Solve the following differential equation.

`y^3 - dy/dx = x dy/dx`


Choose the correct alternative.

The solution of `x dy/dx = y` log y is


Solve the differential equation (x2 – yx2)dy + (y2 + xy2)dx = 0


Solve: `("d"y)/("d"x) + 2/xy` = x2 


Solve the following differential equation 

sec2 x tan y dx + sec2 y tan x dy = 0

Solution: sec2 x tan y dx + sec2 y tan x dy = 0

∴ `(sec^2x)/tanx  "d"x + square` = 0

Integrating, we get

`square + int (sec^2y)/tany  "d"y` = log c

Each of these integral is of the type

`int ("f'"(x))/("f"(x))  "d"x` = log |f(x)| + log c

∴ the general solution is

`square + log |tan y|` = log c

∴ log |tan x . tan y| = log c

`square`

This is the general solution.


Find the particular solution of the following differential equation

`("d"y)/("d"x)` = e2y cos x, when x = `pi/6`, y = 0.

Solution: The given D.E. is `("d"y)/("d"x)` = e2y cos x

∴ `1/"e"^(2y)  "d"y` = cos x dx

Integrating, we get

`int square  "d"y` = cos x dx

∴ `("e"^(-2y))/(-2)` = sin x + c1

∴ e–2y = – 2sin x – 2c1

∴ `square` = c, where c = – 2c

This is general solution.

When x = `pi/6`, y = 0, we have

`"e"^0 + 2sin  pi/6` = c

∴ c = `square`

∴ particular solution is `square`


Given that `"dy"/"dx"` = yex and x = 0, y = e. Find the value of y when x = 1.


The integrating factor of the differential equation `"dy"/"dx" (x log x) + y` = 2logx is ______.


Integrating factor of the differential equation `x "dy"/"dx" - y` = sinx is ______.


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