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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Choose the correct option from the given alternatives: The solution of xdydxx1x⋅dydx=tan-1x is

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प्रश्न

Choose the correct option from the given alternatives:

The solution of `1/"x" * "dy"/"dx" = tan^-1 "x"` is

पर्याय

  • `("x"^2 tan^-1 "x")/2 + "c" = 0`

  • x tan-1 x + c = 0

  • x - tan-1 x = c 

  • y = `("x"^2 tan^-1 "x")/2 - 1/2 ("x" - tan^-1 "x") + "c"`

MCQ
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उत्तर

y = `("x"^2 tan^-1 "x")/2 - 1/2 ("x" - tan^-1 "x") + "c"`

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पाठ 6: Differential Equations - Miscellaneous exercise 1 [पृष्ठ २१५]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 6 Differential Equations
Miscellaneous exercise 1 | Q 1.06 | पृष्ठ २१५

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

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\[\frac{dy}{dx} = \frac{1 - \cos x}{1 + \cos x}\]

\[\frac{dy}{dx} = \tan^{- 1} x\]


\[\frac{dy}{dx} = x \log x\]

x cos y dy = (xex log x + ex) dx


xy dy = (y − 1) (x + 1) dx


\[x\frac{dy}{dx} + \cot y = 0\]

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\[xy\frac{dy}{dx} = \left( x + 2 \right)\left( y + 2 \right), y\left( 1 \right) = - 1\]

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Solution D.E.
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Solution D.E
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