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Find the differential equation whose general solution is x3 + y3 = 35ax.

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प्रश्न

Find the differential equation whose general solution is

x3 + y3 = 35ax.

बेरीज
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उत्तर

x3 + y3 = 35ax ...(i)

Differentiating w.r.t. x, we get

`3x^3 + 3y^3 dy/dx = 35a` ...(ii)

Substituting (ii) in (i), we get

`x^3 + y^3 = (3x^2 + 3y^2 dy/dx)x`

∴ `x^3 + y^3 = 3x^3 + 3x*y^2 dy/dx`

∴ `2x^3 - y^3 +3xy^2dy/dx =0`, which is the required differential equation.

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पाठ 8: Differential Equation and Applications - Exercise 8.2 [पृष्ठ १६३]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 8 Differential Equation and Applications
Exercise 8.2 | Q 4 | पृष्ठ १६३

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