मराठी

X D Y D X + 1 = 0 ; Y ( − 1 ) = 0 - Mathematics

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प्रश्न

\[x\frac{dy}{dx} + 1 = 0 ; y \left( - 1 \right) = 0\]
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उत्तर

We have, 
\[x\frac{dy}{dx} + 1 = 0\]
\[ \Rightarrow \frac{dy}{dx} = \frac{- 1}{x}\]
\[ \Rightarrow dy = \left( \frac{- 1}{x} \right)dx\]
Integrating both sides, we get
\[ \Rightarrow \int dy = \int\left( \frac{- 1}{x} \right)dx\]
\[ \Rightarrow y = - \log\left| x \right| + C . . . . . \left( 1 \right)\]
\[\text{ It is given that }y\left( - 1 \right) = 0 . \]
\[ \therefore 0 = - \log\left| - 1 \right| + C\]
\[ \Rightarrow C = 0\]
\[\text{ Substituting the value of C in }\left( 1 \right),\text{ we get } \]
\[y = - \log\left| x \right|\]
\[\text{ Hence, }y = - \log\left| x \right|\text{ is the solution to the given differential equation .}\]
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पाठ 22: Differential Equations - Exercise 22.05 [पृष्ठ ३४]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 22 Differential Equations
Exercise 22.05 | Q 25 | पृष्ठ ३४

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