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In the following example, verify that the given function is a solution of the corresponding differential equation. Solution D.E. xy = log y + k y' (1 - xy) = y2 - Mathematics and Statistics

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प्रश्न

In the following example, verify that the given function is a solution of the corresponding differential equation.

Solution D.E.
xy = log y + k y' (1 - xy) = y2
बेरीज
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उत्तर

xy = log y + k

Differentiating w.r.t. x, we get

`x dy/dx+ y (1) = 1/y.dy/dx`

∴ `xy dy/dx+ y ^2 = dy/dx`

∴ `dy/dx- x y  dy/dx = y^2`

∴ `(1-xy)dy/dx = y^2`

∴ `y' (1-xy) = y^2`

∴ Given function is a solution of the given differential equation.

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पाठ 8: Differential Equation and Applications - Exercise 8.1 [पृष्ठ १६२]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 8 Differential Equation and Applications
Exercise 8.1 | Q 2.1 | पृष्ठ १६२

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