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प्रश्न
`dy/dx = log x`
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उत्तर
`dy/dx = log x`
∴ dy = log x dx
Integrating on both sides, we get
∫ 1 dy =∫ (log x × 1) dx
∴ `y = log x ( int1dx ) – int [ d/dx (logx) int 1dx] `
∴ `y = log x(x) – int (1/x xx x ) dx`
= x log x – ∫ 1dx
∴ y = x log x – x + c
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