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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

Solve the following differential equation. (x+a)dydx=–y+a

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प्रश्न

Solve the following differential equation.

`(x + a) dy/dx = – y + a`

बेरीज
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उत्तर

`(x + a) dy/dx = – y + a`

∴ `dy/dx + y/((x+a)) = a / ((x+a))`

The given equation is of the form

`dy/ dx + py = Q`

where, `P = 1/((x+a)) and Q = a/((x+a))`

∴ I.F. = `e ^(int^(pdx) = e ^(int^(1/(x+a))^dx)`

= `e^(log^ |x+a|) = (x+a)` 

∴ Solution of the given equation is

`y ( I.F.) = int Q (I.F.) dx + c `

∴ `y(x + a) = int a/((x+a)) (x+a) dx + c`

∴ `y(x + a) = a int 1  dx + c`

∴ y (x + a) = ax + c

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पाठ 8: Differential Equation and Applications - Exercise 8.5 [पृष्ठ १६८]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 8 Differential Equation and Applications
Exercise 8.5 | Q 1.7 | पृष्ठ १६८

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