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Choose the correct option from the given alternatives: The solution of x + ydydx(x + y)2dydx=1 is - Mathematics and Statistics

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प्रश्न

Choose the correct option from the given alternatives:

The solution of `("x + y")^2 "dy"/"dx" = 1` is

पर्याय

  • x = tan-1 (x + y) + c

  • y tan-1 `("x"/"y") = "c"`

  • y = tan-1 (x + y) + c

  • y + tan-1 (x + y) + c

MCQ
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उत्तर

y = tan-1 (x + y) + c

Hint:

`("x + y")^2 "dy"/"dx" = 1`

Put x + y = u      ∴ `1 + "dy"/"dx" = "du"/"dx"`

∴ `"u"^2 ("du"/"dx" - 1) = 1`

∴ `"u"^2 "du"/"dx" = "u"^2 + 1`

∴ `int "u"^2/("u"^2 + 1) "du" = int "dx"`

∴ `int (("u"^2 + 1) - 1)/("u"^2 + 1) "du" = int "dx"`

∴ `int (1 - 1/"u")"du" = int "dx"`

∴ u - tan-1 u = x + c

∴ x + y - tan-1 (x + y) = x + c

∴ y = tan-1 (x + y) + c.

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Formation of Differential Equations
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Differential Equations - Miscellaneous exercise 1 [पृष्ठ २१५]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 6 Differential Equations
Miscellaneous exercise 1 | Q 1.07 | पृष्ठ २१५

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