मराठी

D Y D X = E X + Y + E − X + Y

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प्रश्न

\[\frac{dy}{dx} = e^{x + y} + e^{- x + y}\]
बेरीज
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उत्तर

We have, 
\[\frac{dy}{dx} = e^{x + y} + e^{- x + y} \]
\[ \Rightarrow \frac{dy}{dx} = e^y \left( e^x + e^{- x} \right)\]
\[ \Rightarrow e^{- y} dy = \left( e^x + e^{- x} \right) dx\]
Integrating both sides, we get
\[\int e^{- y} dy = \int\left( e^x + e^{- x} \right) dx\]
\[ \Rightarrow - e^{- y} = e^x - e^{- x} + C\]
\[ \Rightarrow e^{- x} - e^{- y} = e^x + C\]
\[\text{ Hence, } e^{- x} - e^{- y} = e^x + C\text{ is the required solution.} \]

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पाठ 21: Differential Equations - Exercise 22.07 [पृष्ठ ५५]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 21 Differential Equations
Exercise 22.07 | Q 35 | पृष्ठ ५५

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

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