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Determine the order and degree of the following differential equations. Solution D.E. ax2 + by2 = 5 xyd2ydx2+x(dydx)2=ydydx - Mathematics and Statistics

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प्रश्न

Determine the order and degree of the following differential equations.

Solution D.E.
ax2 + by2 = 5 `xy(d^2y)/dx^2+ x(dy/dx)^2 = y dy/dx`
बेरीज
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उत्तर

ax 2 + by 2 = 5

Differentiating w.r.t. x, we get

`2ax +2by dy/dx = 0` ....(i)

Again, differentiating w.r.t. x, we get

`2a + 2b(dy/dx)^2 + 2by ((d^2y)/dx^2) = 0` ........(ii)

From (i), we get

`a = - (by)/x(dy/dx)`

Substituting the value of a in (ii), we get

`- 2(by)/x(dy/dx) + 2b(dy/dx)^2 + 2by((d^2y)/dx^2) = 0`

∴`- y/x(dy/dx) + (dy/dx)^2 + y((d^2y)/dx^2) = 0`

∴`- y(dy/dx) + x(dy/dx)^2 + xy((d^2y)/dx^2) = 0`

∴`x y((d^2y)/dx^2) + x(dy/dx)^2 =y((dy)/dx) `

∴ Given function is a solution of the given differential equation.

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पाठ 8: Differential Equation and Applications - Exercise 8.1 [पृष्ठ १६२]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 8 Differential Equation and Applications
Exercise 8.1 | Q 2.6 | पृष्ठ १६२

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