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Cos X Cos Y D Y D X = − Sin X Sin Y - Mathematics

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प्रश्न

\[\cos x \cos y\frac{dy}{dx} = - \sin x \sin y\]
बेरीज
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उत्तर

We have,
\[\cos x \cos y \frac{dy}{dx} = - \sin x \sin y \]
\[ \Rightarrow \frac{\cos y}{\sin y}dy = \frac{- \sin x}{\cos x}dx\]
\[ \Rightarrow \cot y\ dy = - \tan x\ dx\]
Integrating both sides, we get 
\[\int \cot y\ dy = - \int\tan x\ dx\]
\[ \Rightarrow \log \left| \sin y \right| = - \log \left| \sec x \right| + \log C\]
\[ \Rightarrow \log \left| \sin y \right| = \log \left| \cos x \right| + \log C\]
\[ \Rightarrow \sin y = C \cos x\]
\[\text{ Hence, }\sin y = C \cos x\text{ is the required solution . }\]

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पाठ 22: Differential Equations - Exercise 22.07 [पृष्ठ ५५]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 22 Differential Equations
Exercise 22.07 | Q 25 | पृष्ठ ५५

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