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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

Choose the correct alternative: Differential equation of the function c + 4yx = 0 is

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प्रश्न

Choose the correct alternative:

Differential equation of the function c + 4yx = 0 is

पर्याय

  • `xy + ("d"y)/("d"x)` = 0

  • `x ("d"y)/("d"x) + y` = 0

  • `("d"y)/("d"x) - 4xy` =0

  • `x ("d"y)/("d"x) + 1` = 0

MCQ
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उत्तर

`x ("d"y)/("d"x) + y` = 0

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पाठ 1.8: Differential Equation and Applications - Q.1

संबंधित प्रश्‍न

Show that the differential equation of which y = 2(x2 − 1) + \[c e^{- x^2}\] is a solution, is \[\frac{dy}{dx} + 2xy = 4 x^3\]


Form the differential equation of the family of hyperbolas having foci on x-axis and centre at the origin.


For the following differential equation verify that the accompanying function is a solution:

Differential equation Function
\[x + y\frac{dy}{dx} = 0\]
\[y = \pm \sqrt{a^2 - x^2}\]

Differential equation \[\frac{d^2 y}{d x^2} + y = 0, y \left( 0 \right) = 1, y' \left( 0 \right) = 1\] Function y = sin x + cos x


\[\left( x - 1 \right)\frac{dy}{dx} = 2 x^3 y\]

xy dy = (y − 1) (x + 1) dx


\[\sqrt{1 + x^2} dy + \sqrt{1 + y^2} dx = 0\]

Solve the following differential equation:
\[\left( 1 + y^2 \right) \tan^{- 1} xdx + 2y\left( 1 + x^2 \right)dy = 0\]


\[\frac{dr}{dt} = - rt, r\left( 0 \right) = r_0\]

\[2x\frac{dy}{dx} = 5y, y\left( 1 \right) = 1\]

\[\frac{dy}{dx} = 2 e^{2x} y^2 , y\left( 0 \right) = - 1\]

Solve the differential equation \[\frac{dy}{dx} = \frac{2x\left( \log x + 1 \right)}{\sin y + y \cos y}\], given that y = 0, when x = 1.


\[\cos^2 \left( x - 2y \right) = 1 - 2\frac{dy}{dx}\]

\[\frac{dy}{dx} + 1 = e^{x + y}\]

Experiments show that radium disintegrates at a rate proportional to the amount of radium present at the moment. Its half-life is 1590 years. What percentage will disappear in one year?


Find the equation of the curve which passes through the point (2, 2) and satisfies the differential equation
\[y - x\frac{dy}{dx} = y^2 + \frac{dy}{dx}\]


Find the equation to the curve satisfying x (x + 1) \[\frac{dy}{dx} - y\]  = x (x + 1) and passing through (1, 0).


Write the differential equation obtained by eliminating the arbitrary constant C in the equation x2 − y2 = C2.


If sin x is an integrating factor of the differential equation \[\frac{dy}{dx} + Py = Q\], then write the value of P.


In the following example, verify that the given function is a solution of the corresponding differential equation.

Solution D.E.
xy = log y + k y' (1 - xy) = y2

Form the differential equation from the relation x2 + 4y2 = 4b2


Choose the correct alternative.

The differential equation of y = `k_1 + k_2/x` is


Solve

`dy/dx + 2/ x y = x^2`


Solve the following differential equation

`yx ("d"y)/("d"x)` = x2 + 2y2 


Solve the following differential equation 

sec2 x tan y dx + sec2 y tan x dy = 0

Solution: sec2 x tan y dx + sec2 y tan x dy = 0

∴ `(sec^2x)/tanx  "d"x + square` = 0

Integrating, we get

`square + int (sec^2y)/tany  "d"y` = log c

Each of these integral is of the type

`int ("f'"(x))/("f"(x))  "d"x` = log |f(x)| + log c

∴ the general solution is

`square + log |tan y|` = log c

∴ log |tan x . tan y| = log c

`square`

This is the general solution.


Integrating factor of the differential equation `"dy"/"dx" - y` = cos x is ex.


Solve: `("d"y)/("d"x) = cos(x + y) + sin(x + y)`. [Hint: Substitute x + y = z]


Solution of `x("d"y)/("d"x) = y + x tan  y/x` is `sin(y/x)` = cx


The differential equation (1 + y2)x dx – (1 + x2)y dy = 0 represents a family of:


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