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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

A solution of differential equation which can be obtained from the general solution by giving particular values to the arbitrary constant is called ______ solution

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प्रश्न

A solution of differential equation which can be obtained from the general solution by giving particular values to the arbitrary constant is called ______ solution

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उत्तर

particular

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पाठ 1.8: Differential Equation and Applications - Q.2

संबंधित प्रश्‍न

Differential equation \[\frac{d^2 y}{d x^2} - 2\frac{dy}{dx} + y = 0, y \left( 0 \right) = 1, y' \left( 0 \right) = 2\] Function y = xex + ex


\[\frac{dy}{dx} = x^5 + x^2 - \frac{2}{x}, x \neq 0\]

\[\frac{dy}{dx} = \frac{1 - \cos x}{1 + \cos x}\]

\[\frac{dy}{dx} = x \log x\]

\[\frac{dy}{dx} = \frac{1 + y^2}{y^3}\]

xy dy = (y − 1) (x + 1) dx


\[\frac{dy}{dx} = \frac{x e^x \log x + e^x}{x \cos y}\]

dy + (x + 1) (y + 1) dx = 0


\[\left( x - 1 \right)\frac{dy}{dx} = 2 x^3 y\]

\[\frac{dy}{dx} = e^{x + y} + e^{- x + y}\]

\[2xy\frac{dy}{dx} = x^2 + y^2\]

\[xy\frac{dy}{dx} = x^2 - y^2\]

3x2 dy = (3xy + y2) dx


Solve the following differential equations:
\[\frac{dy}{dx} = \frac{y}{x}\left\{ \log y - \log x + 1 \right\}\]


Solve the following initial value problem:-

\[x\frac{dy}{dx} - y = \left( x + 1 \right) e^{- x} , y\left( 1 \right) = 0\]


Solve the following initial value problem:
\[x\frac{dy}{dx} + y = x \cos x + \sin x, y\left( \frac{\pi}{2} \right) = 1\]


Solve the following initial value problem:-

\[\frac{dy}{dx} + 2y \tan x = \sin x; y = 0\text{ when }x = \frac{\pi}{3}\]


Solve the following initial value problem:-

\[\frac{dy}{dx} - 3y \cot x = \sin 2x; y = 2\text{ when }x = \frac{\pi}{2}\]


A population grows at the rate of 5% per year. How long does it take for the population to double?


Write the differential equation obtained by eliminating the arbitrary constant C in the equation x2 − y2 = C2.


If xmyn = (x + y)m+n, prove that \[\frac{dy}{dx} = \frac{y}{x} .\]


y2 dx + (x2 − xy + y2) dy = 0


Determine the order and degree of the following differential equations.

Solution D.E.
y = 1 − logx `x^2(d^2y)/dx^2 = 1`

Solve the following differential equation.

`dy/dx + y` = 3


Solve the differential equation:

dr = a r dθ − θ dr


Solve the following differential equation y log y = `(log  y - x) ("d"y)/("d"x)`


Solve the following differential equation y2dx + (xy + x2) dy = 0


Verify y = `a + b/x` is solution of `x(d^2y)/(dx^2) + 2 (dy)/(dx)` = 0

y = `a + b/x`

`(dy)/(dx) = square`

`(d^2y)/(dx^2) = square`

Consider `x(d^2y)/(dx^2) + 2(dy)/(dx)`

= `x square + 2 square`

= `square`

Hence y = `a + b/x` is solution of `square`


Solve: `("d"y)/("d"x) = cos(x + y) + sin(x + y)`. [Hint: Substitute x + y = z]


Solve the differential equation

`x + y dy/dx` = x2 + y2


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