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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

A solution of differential equation which can be obtained from the general solution by giving particular values to the arbitrary constant is called ______ solution

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प्रश्न

A solution of differential equation which can be obtained from the general solution by giving particular values to the arbitrary constant is called ______ solution

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उत्तर

particular

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पाठ 1.8: Differential Equation and Applications - Q.2

संबंधित प्रश्‍न

For the following differential equation verify that the accompanying function is a solution:

Differential equation Function
\[x\frac{dy}{dx} + y = y^2\]
\[y = \frac{a}{x + a}\]

Differential equation \[\frac{d^2 y}{d x^2} - 3\frac{dy}{dx} + 2y = 0, y \left( 0 \right) = 1, y' \left( 0 \right) = 3\] Function y = ex + e2x


\[\frac{dy}{dx} = \frac{1 - \cos x}{1 + \cos x}\]

\[\frac{dy}{dx} = \sin^2 y\]

\[\frac{dy}{dx} = \frac{x e^x \log x + e^x}{x \cos y}\]

tan y dx + sec2 y tan x dy = 0


(1 + x) (1 + y2) dx + (1 + y) (1 + x2) dy = 0


\[x^2 \frac{dy}{dx} = x^2 - 2 y^2 + xy\]

Solve the following initial value problem:-

\[y' + y = e^x , y\left( 0 \right) = \frac{1}{2}\]


The surface area of a balloon being inflated, changes at a rate proportional to time t. If initially its radius is 1 unit and after 3 seconds it is 2 units, find the radius after time t.


Find the equation of the curve such that the portion of the x-axis cut off between the origin and the tangent at a point is twice the abscissa and which passes through the point (1, 2).


The x-intercept of the tangent line to a curve is equal to the ordinate of the point of contact. Find the particular curve through the point (1, 1).


Write the differential equation obtained by eliminating the arbitrary constant C in the equation x2 − y2 = C2.


The integrating factor of the differential equation (x log x)
\[\frac{dy}{dx} + y = 2 \log x\], is given by


y2 dx + (x2 − xy + y2) dy = 0


Form the differential equation of the family of circles having centre on y-axis and radius 3 unit.


Solve the following differential equation.

`(dθ)/dt  = − k (θ − θ_0)`


Solve the following differential equation.

dr + (2r)dθ= 8dθ


Select and write the correct alternative from the given option for the question

Bacterial increases at the rate proportional to the number present. If original number M doubles in 3 hours, then number of bacteria will be 4M in


For the differential equation, find the particular solution (x – y2x) dx – (y + x2y) dy = 0 when x = 2, y = 0


Solve the following differential equation y2dx + (xy + x2) dy = 0


The function y = ex is solution  ______ of differential equation


Solve the following differential equation `("d"y)/("d"x)` = x2y + y


Solve the following differential equation `("d"y)/("d"x)` = cos(x + y)

Solution: `("d"y)/("d"x)` = cos(x + y)    ......(1)

Put `square`

∴ `1 + ("d"y)/("d"x) = "dv"/("d"x)`

∴ `("d"y)/("d"x) = "dv"/("d"x) - 1`

∴ (1) becomes `"dv"/("d"x) - 1` = cos v

∴ `"dv"/("d"x)` = 1 + cos v

∴ `square` dv = dx

Integrating, we get

`int 1/(1 + cos "v")  "d"v = int  "d"x`

∴ `int 1/(2cos^2 ("v"/2))  "dv" = int  "d"x`

∴ `1/2 int square  "dv" = int  "d"x`

∴ `1/2* (tan("v"/2))/(1/2)` = x + c

∴ `square` = x + c


Solve the differential equation `"dy"/"dx" + 2xy` = y


lf the straight lines `ax + by + p` = 0 and `x cos alpha + y sin alpha = p` are inclined at an angle π/4 and concurrent with the straight line `x sin alpha - y cos alpha` = 0, then the value of `a^2 + b^2` is


`d/(dx)(tan^-1  (sqrt(1 + x^2) - 1)/x)` is equal to:


Solve the differential equation

`y (dy)/(dx) + x` = 0


In mathematics and science, what primary purpose do differential equations serve?


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