मराठी

Xy Dy = (Y − 1) (X + 1) Dx

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प्रश्न

xy dy = (y − 1) (x + 1) dx

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उत्तर

We have,
\[xy dy = \left( y - 1 \right)\left( x + 1 \right) dx\]
\[ \Rightarrow \frac{y}{y - 1}dy = \frac{x + 1}{x}dx\]
Integrating both sides, we get
\[\int\frac{y}{y - 1}dy = \int\frac{x + 1}{x}dx\]
\[ \Rightarrow \int\frac{y - 1 + 1}{y - 1}dy = \int\frac{x + 1}{x}dx\]
\[ \Rightarrow \int dy + \int\frac{1}{y - 1}dy = \int dx + \int\frac{1}{x}dx\]
\[ \Rightarrow y + \log \left| y - 1 \right| = x + \log \left| x \right| + C\]
\[ \Rightarrow y - x = \log\left| x \right| - \log\left| y - 1 \right| + C\]
\[\text{ Hence, }y - x = \log \left| x \right| - \log \left| y - 1 \right| + \text{ C is the required solution .} \]

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पाठ 21: Differential Equations - Exercise 22.07 [पृष्ठ ५५]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 21 Differential Equations
Exercise 22.07 | Q 12 | पृष्ठ ५५

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