हिंदी

Choose the correct alternative: Differential equation of the function c + 4yx = 0 is

Advertisements
Advertisements

प्रश्न

Choose the correct alternative:

Differential equation of the function c + 4yx = 0 is

विकल्प

  • `xy + ("d"y)/("d"x)` = 0

  • `x ("d"y)/("d"x) + y` = 0

  • `("d"y)/("d"x) - 4xy` =0

  • `x ("d"y)/("d"x) + 1` = 0

MCQ
Advertisements

उत्तर

`x ("d"y)/("d"x) + y` = 0

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1.8: Differential Equation and Applications - Q.1

संबंधित प्रश्न

\[\left( \frac{dy}{dx} \right)^2 + \frac{1}{dy/dx} = 2\]

\[y\frac{d^2 x}{d y^2} = y^2 + 1\]

\[x^2 \left( \frac{d^2 y}{d x^2} \right)^3 + y \left( \frac{dy}{dx} \right)^4 + y^4 = 0\]

Show that y = ax3 + bx2 + c is a solution of the differential equation \[\frac{d^3 y}{d x^3} = 6a\].

 


\[\frac{dy}{dx} + 2x = e^{3x}\]

\[\frac{1}{x}\frac{dy}{dx} = \tan^{- 1} x, x \neq 0\]

\[\left( x^3 + x^2 + x + 1 \right)\frac{dy}{dx} = 2 x^2 + x\]

xy (y + 1) dy = (x2 + 1) dx


\[\sqrt{1 + x^2 + y^2 + x^2 y^2} + xy\frac{dy}{dx} = 0\]

If y(x) is a solution of the different equation \[\left( \frac{2 + \sin x}{1 + y} \right)\frac{dy}{dx} = - \cos x\] and y(0) = 1, then find the value of y(π/2).


\[\frac{dy}{dx}\cos\left( x - y \right) = 1\]

(x + y) (dx − dy) = dx + dy


Solve the following initial value problem:-
\[\tan x\left( \frac{dy}{dx} \right) = 2x\tan x + x^2 - y; \tan x \neq 0\] given that y = 0 when \[x = \frac{\pi}{2}\]


If the marginal cost of manufacturing a certain item is given by C' (x) = \[\frac{dC}{dx}\] = 2 + 0.15 x. Find the total cost function C (x), given that C (0) = 100.

 

Find the curve for which the intercept cut-off by a tangent on x-axis is equal to four times the ordinate of the point of contact.

 

Find the equation to the curve satisfying x (x + 1) \[\frac{dy}{dx} - y\]  = x (x + 1) and passing through (1, 0).


A curve is such that the length of the perpendicular from the origin on the tangent at any point P of the curve is equal to the abscissa of P. Prove that the differential equation of the curve is \[y^2 - 2xy\frac{dy}{dx} - x^2 = 0\], and hence find the curve.


The integrating factor of the differential equation \[\left( 1 - y^2 \right)\frac{dx}{dy} + yx = ay\left( - 1 < y < 1 \right)\] is ______.


y2 dx + (x2 − xy + y2) dy = 0


Choose the correct option from the given alternatives:

The solution of `1/"x" * "dy"/"dx" = tan^-1 "x"` is


For each of the following differential equations find the particular solution.

(x − y2 x) dx − (y + x2 y) dy = 0, when x = 2, y = 0


Solve the differential equation:

dr = a r dθ − θ dr


Solve

`dy/dx + 2/ x y = x^2`


Solve the differential equation `("d"y)/("d"x) + y` = e−x 


Solve the following differential equation y2dx + (xy + x2) dy = 0


State whether the following statement is True or False:

The integrating factor of the differential equation `("d"y)/("d"x) - y` = x is e–x 


Solve the following differential equation

`y log y ("d"x)/("d"y) + x` = log y


The differential equation of all non horizontal lines in a plane is `("d"^2x)/("d"y^2)` = 0


Which of the following defines a differential equation?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×