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Form the differential equation from the relation x2 + 4y2 = 4b2

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प्रश्न

Form the differential equation from the relation x2 + 4y2 = 4b2

योग
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उत्तर

Given relation is

x2 + 4y2 = 4b2

Differentiating w.r.t. x, we get

`2x + 4.2y ("d"y)/("d"x) = 0`

∴ `x + 4y ("d"y)/("d"x)  = 0`, which is the required differential equation.

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अध्याय 1.8: Differential Equation and Applications - Q.5

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 8 Differential Equation and Applications
Exercise 8.2 | Q 5 | पृष्ठ १६३

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