हिंदी

Solve the following differential equation. θθθdθdt =−k(θ−θO)

Advertisements
Advertisements

प्रश्न

Solve the following differential equation.

`(dθ)/dt  = − k (θ − θ_0)`

योग
Advertisements

उत्तर

`(dθ)/dt  = − k (θ − θ_0)`, k is constant.

∴`(dθ)/ (θ − θ_0) = -k dt`

Integrating on both sides, we get

`int(dθ)/ (θ − θ_0)  = -k int dt`

∴ log |θ − θ0| = - kt + c

∴ θ − θ0 = `e ^(-kt+c)`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Differential Equation and Applications - Exercise 8.3 [पृष्ठ १६५]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 8 Differential Equation and Applications
Exercise 8.3 | Q 1.2 | पृष्ठ १६५

संबंधित प्रश्न

\[\frac{d^2 y}{d x^2} + 4y = 0\]

\[\frac{d^4 y}{d x^4} = \left\{ c + \left( \frac{dy}{dx} \right)^2 \right\}^{3/2}\]

For the following differential equation verify that the accompanying function is a solution:

Differential equation Function
\[x + y\frac{dy}{dx} = 0\]
\[y = \pm \sqrt{a^2 - x^2}\]

Differential equation \[\frac{d^2 y}{d x^2} - \frac{dy}{dx} = 0, y \left( 0 \right) = 2, y'\left( 0 \right) = 1\]

Function y = ex + 1


Differential equation \[\frac{dy}{dx} + y = 2, y \left( 0 \right) = 3\] Function y = e−x + 2


Differential equation \[\frac{d^2 y}{d x^2} - 3\frac{dy}{dx} + 2y = 0, y \left( 0 \right) = 1, y' \left( 0 \right) = 3\] Function y = ex + e2x


\[\frac{dy}{dx} = \tan^{- 1} x\]


\[\sin^4 x\frac{dy}{dx} = \cos x\]

\[\frac{dy}{dx} + \frac{1 + y^2}{y} = 0\]

\[\frac{dy}{dx} = \left( e^x + 1 \right) y\]

\[y\sqrt{1 + x^2} + x\sqrt{1 + y^2}\frac{dy}{dx} = 0\]

\[\frac{dy}{dx} = \frac{e^x \left( \sin^2 x + \sin 2x \right)}{y\left( 2 \log y + 1 \right)}\]

\[\frac{dy}{dx} = y \tan 2x, y\left( 0 \right) = 2\] 

Solve the differential equation \[\frac{dy}{dx} = \frac{2x\left( \log x + 1 \right)}{\sin y + y \cos y}\], given that y = 0, when x = 1.


\[\frac{dy}{dx} = \left( x + y + 1 \right)^2\]

(x + y) (dx − dy) = dx + dy


Solve the following initial value problem:-

\[\frac{dy}{dx} - 3y \cot x = \sin 2x; y = 2\text{ when }x = \frac{\pi}{2}\]


The surface area of a balloon being inflated, changes at a rate proportional to time t. If initially its radius is 1 unit and after 3 seconds it is 2 units, find the radius after time t.


The tangent at any point (x, y) of a curve makes an angle tan−1(2x + 3y) with x-axis. Find the equation of the curve if it passes through (1, 2).


At every point on a curve the slope is the sum of the abscissa and the product of the ordinate and the abscissa, and the curve passes through (0, 1). Find the equation of the curve.


The rate of increase of bacteria in a culture is proportional to the number of bacteria present and it is found that the number doubles in 6 hours. Prove that the bacteria becomes 8 times at the end of 18 hours.


What is integrating factor of \[\frac{dy}{dx}\] + y sec x = tan x?


Form the differential equation representing the family of curves y = a sin (x + b), where ab are arbitrary constant.


If a + ib = `("x" + "iy")/("x" - "iy"),` prove that `"a"^2 +"b"^2 = 1` and `"b"/"a" = (2"xy")/("x"^2 - "y"^2)`


Solve the following differential equation.

y dx + (x - y2 ) dy = 0


The integrating factor of the differential equation `dy/dx - y = x` is e−x.


Solve the differential equation (x2 – yx2)dy + (y2 + xy2)dx = 0


Solve the following differential equation `("d"y)/("d"x)` = x2y + y


An appropriate substitution to solve the differential equation `"dx"/"dy" = (x^2 log(x/y) - x^2)/(xy log(x/y))` is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×