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Solve the following differential equation. dydx=x2y+y

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प्रश्न

Solve the following differential equation.

`dy/dx = x^2 y + y`

योग
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उत्तर

`dy/dx = x^2 y + y = (x^2 +1)y`

∴ `1/y dy = (x^2 + 1)dx`

Integrating on both sides, we get

` int 1/y dy  = int (x^2+1) dx`

∴ `log  | y | = x^3/3 + x + c`

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अध्याय 8: Differential Equation and Applications - Exercise 8.3 [पृष्ठ १६५]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 8 Differential Equation and Applications
Exercise 8.3 | Q 1.1 | पृष्ठ १६५

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