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Solve the following differential equation. dydx+2xy=x

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प्रश्न

Solve the following differential equation.

`dy/dx + 2xy = x`

योग
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उत्तर

`dy/dx + 2xy = x`

The given equation is of the form

`dy/dx + py = Q`

where, P = 2x and Q = x

∴ `I.F. = e^(intPdx) = e^ (int ^(2x  dx) = e^(x^2)`

∴ Solution of the given equation is

y(I.F.) = `int Q ( I.F.) dx +c`

∴ `y e ^(x^2)  int xe^(x^2) dx + c `

In R. H. S., put x2 = t

Differentiating w.r.t. x, we get

2x dx = dt 

∴ `ye^(x^2) = int e^t dt/2 + c `

= `1/2 int e^t dt+ c `

= `e^t/2 + c`

∴ `y e ^(x^2) = 1/2 e^(x^2) + c`

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अध्याय 8: Differential Equation and Applications - Exercise 8.5 [पृष्ठ १६८]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 8 Differential Equation and Applications
Exercise 8.5 | Q 1.6 | पृष्ठ १६८

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