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Question
The area of a parallelogram is y cm2 and its height is h cm. The base of another parallelogram is x cm more than the base of the first parallelogram and its area is twice the area of the first. Find, in terms of y, h, and x, the expression for the height of the second parallelogram.
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Solution
Let 'y' and 'h' be the area and the height of the first parallelogram respectively.
Let 'height' be the height of the second parallelogram
base of the first parallelogram = `y/h`cm
the base of the second parallelogram = `( y/h + x )` cm
`( y/h + x )` x height = 2y
height = `[2hy]/[ y + hx ]`
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