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Question
The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.
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Solution
Given:
Perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m.
Now, we know:
Area \[= \frac{1}{2} \times d \times ( h_1 + h_2 )\]
∴ Area of the field \[= \frac{1}{2} \times 24 \times (8 + 13)\]
\[ = 12 \times 21\]
\[ = 252 m^2\]
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