Advertisements
Advertisements
प्रश्न
The area of a parallelogram is y cm2 and its height is h cm. The base of another parallelogram is x cm more than the base of the first parallelogram and its area is twice the area of the first. Find, in terms of y, h, and x, the expression for the height of the second parallelogram.
Advertisements
उत्तर
Let 'y' and 'h' be the area and the height of the first parallelogram respectively.
Let 'height' be the height of the second parallelogram
base of the first parallelogram = `y/h`cm
the base of the second parallelogram = `( y/h + x )` cm
`( y/h + x )` x height = 2y
height = `[2hy]/[ y + hx ]`
APPEARS IN
संबंधित प्रश्न
The distance between parallel sides of a trapezium is 15 cm and the length of the line segment joining the mid-points of its non-parallel sides is 26 cm. Find the area of the trapezium.
ABCD is a square with each side 12 cm. P is a point on BC such that area of ΔABP: area of trapezium APCD = 1: 5. Find the length of CP.
Trapezium given below; find its area.
Trapezium given below; find its area.
The figure given below shows the cross-section of a concrete structure. Calculate the area of cross-section if AB = 1.8 cm, CD = 0.6 m, DE = 0.8 m, EF = 0.3 m and AF = 1.2 m.
Two adjacent sides of a parallelogram are 24 cm and 18 cm. If the distance between the longer sides is 12 cm; find the distance between the shorter sides.
Two adjacent sides of a parallelogram are 28 cm and 26 cm. If one diagonal of it is 30 cm long; find the area of the parallelogram. Also, find the distance between its shorter sides.
Find the area of quadrilateral BCEG
If vertices of a quadrilateral are at A(– 5, 7), B(– 4, k), C(– 1, – 6) and D(4, 5) and its area is 72 sq. units. Find the value of k.
If the diagonal d of a quadrilateral is doubled and the heights h1 and h2 falling on d are halved, then the area of quadrilateral is ______.
