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Solve the following : Find the distance of the point ijk3i^+3j^+k^ from the planerijkr¯.(2i^+3j^+6k^) = 21.

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Question

Solve the following:

Find the distance of the point `3hat"i" + 3hat"j" + hat"k"` from the plane `bar"r".(2hat"i" + 3hat"j" + 6hat"k")` = 21.

Sum
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Solution

The distance of the point `"A"(bara)` from the plane `bar"r".bar"n" = p  "is given by"  d = |bar"a".bar"n" - p|/|bar"n"|`  ...(1)

Here, `bar"a" = 3hat"i" + 3hat"j" + hat"k", bar"n" = 2hat"i" + 3hat"j" + 6hat"k"`, p = 21

∴ `bar"a".bar"n" = (3hat"i" + 3hat"j" + hat"k").(2hat"i" + 3hat"j" + 6hat"k")`

= (3)(2) + (3)(3) + (1)(–6)
= 6 + 9 – 6
= 9
Also, `|bar"n"| = sqrt(3^2 + 3^2 + (-6)^2) = sqrt(-12)` = 0

∴ from (1), the required distance

= `|- 12 - 21|/(12)`

= 0 units.

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Chapter 6: Line and Plane - Miscellaneous Exercise 6 B [Page 226]

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