Advertisements
Advertisements
Question
Solve for x, `log_x^(15√5) = 2 - log_x^(3√5)`.
Advertisements
Solution
logx15√5 = 2 - logx3√5
⇒ logx15√5 + logx3√5 = 2
⇒ logx( 15√5 x 3√5 ) = 2
⇒ logx 225 = 2
⇒ logx 152 = 2
⇒ 2logx 15 = 2
⇒ logx15 = 1
⇒ x = 15.
APPEARS IN
RELATED QUESTIONS
If x = log 0.6; y = log 1.25 and z = log 3 - 2 log 2, find the values of :
(i) x+y- z
(ii) 5x + y - z
Given : `log x/ log y = 3/2` and log (xy) = 5; find the value of x and y.
Solve : log5( x + 1 ) - 1 = 1 + log5( x - 1 ).
If a2 = log x , b3 = log y and `a^2/2 - b^3/3` = log c , find c in terms of x and y.
Evaluate : `( log _5^8 )/(( log_25 16 ) xx ( log_100 10))`
Solve the following:
log 4 x + log 4 (x-6) = 2
Solve for x: `("log"125)/("log"5)` = logx
Solve for x: `("log"1331)/("log"11)` = logx
State, true of false:
logba =-logab
If log 3 m = x and log 3 n = y, write down
`3^(1-2y+3x)` in terms of m an n
