Advertisements
Advertisements
Question
Given x = log1012 , y = log4 2 x log109 and z = log100.4 , find :
(i) x - y - z
(ii) 13x - y - z
Advertisements
Solution
(i) x - y - z
= log1012 - log42 x log109 - log100.4
= log10( 4 x 3 ) - log42 x log109 - log100.4
= log104 + log103 - log42 x 2log103 - log10`( 4/10 )`
= log104 + log103 - `(log_10 2)/(2log_10 2)` x 2log103 - log104 + log1010
= log104 + log103 - `[ 2log_10 3 ]/2`- log104 + 1
= 1
(ii) 13x - y - z = 131 = 13.
APPEARS IN
RELATED QUESTIONS
If x = 1 + log 2 - log 5, y = 2 log3 and z = log a - log 5; find the value of a if x + y = 2z.
Given : `log x/ log y = 3/2` and log (xy) = 5; find the value of x and y.
Evaluate: `(log_5 8)/(log_25 16 xx Log_100 10)`
Solve for x: `("log"27)/("log"243)` = x
If log x = a and log y = b, write down
10a-1 in terms of x
If log 3 m = x and log 3 n = y, write down
`3^(1-2y+3x)` in terms of m an n
If `"log" x^2 - "log"sqrt(y)` = 1, express y in terms of x. Hence find y when x = 2.
If 2 log x + 1 = log 360, find: log (3 x2 - 8)
Express the following in a form free from logarithm:
3 log x - 2 log y = 2
Express the following in a form free from logarithm:
`2"log" x + 1/2"log" y` = 1
