Loga M ÷ Logab M + 1 + Log Ab - Mathematics

Show that : log_a m ÷ log_ab m + 1 + log _ab

Sum

log_a m ÷ log_ab m = =` ( log_a m )/( log_(ab) m )`

=` ( log_m ab )/( log_(m) a ) [ Qlog_b a = 1/ (log_ab ) ]`

₌ log_a ab `[ Q ( log_xx a) / (log_xx b ) = log_b a ]`

= log_aa + log_a b

= 1 + log_a b

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Chapter 8: Logarithms - Exercise 8 (D) [Page 111]

Chapter 8 Logarithms
Exercise 8 (D) | Q 20 | Page 111

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