Advertisements
Advertisements
Question
Solve for x: `("log"289)/("log"17)` = logx
Advertisements
Solution
`("log"289)/("log"17)` = logx
⇒ `("log"17^2)/("log"17)` = logx
⇒ `(2"log"17)/("log"17)` = logx
⇒ 2 = logx
⇒ 2log10 = logx ...(since log10 = 1)
⇒ log102 = logx
∴ x = 102
= 100.
APPEARS IN
RELATED QUESTIONS
If `3/2 log a + 2/3` log b - 1 = 0, find the value of a9.b4 .
Evaluate :`1/( log_a bc + 1) + 1/(log_b ca + 1) + 1/ ( log_c ab + 1 )`
If a2 = log x, b3 = log y and 3a2 - 2b3 = 6 log z, express y in terms of x and z .
Find x, if : logx 625 = - 4
If p = log 20 and q = log 25 , find the value of x , if 2log( x + 1 ) = 2p - q.
Solve for x, `log_x^(15√5) = 2 - log_x^(3√5)`.
Solve the following:
log (3 - x) - log (x - 3) = 1
Solve for x: `("log"125)/("log"5)` = logx
Prove that log (1 + 2 + 3) = log 1 + log 2 + log 3. Is it true for any three numbers x, y, z?
Prove that `("log"_"p" x)/("log"_"pq" x)` = 1 + logp q
